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1331. 数组序号转换


1331. 数组序号转换

🟢   🔖  数组 哈希表 排序  🔗 力扣open in new window LeetCodeopen in new window

题目

Given an array of integers arr, replace each element with its rank.

The rank represents how large the element is. The rank has the following rules:

  • Rank is an integer starting from 1.
  • The larger the element, the larger the rank. If two elements are equal, their rank must be the same.
  • Rank should be as small as possible.

Example 1:

Input: arr = [40,10,20,30]

Output: [4,1,2,3]

Explanation : 40 is the largest element. 10 is the smallest. 20 is the second smallest. 30 is the third smallest.

Example 2:

Input: arr = [100,100,100]

Output: [1,1,1]

Explanation : Same elements share the same rank.

Example 3:

Input: arr = [37,12,28,9,100,56,80,5,12]

Output: [5,3,4,2,8,6,7,1,3]

Constraints:

  • 0 <= arr.length <= 10^5
  • -10^9 <= arr[i] <= 10^9

题目大意

给你一个整数数组 arr ,请你将数组中的每个元素替换为它们排序后的序号。

序号代表了一个元素有多大。序号编号的规则如下:

  • 序号从 1 开始编号。
  • 一个元素越大,那么序号越大。如果两个元素相等,那么它们的序号相同。
  • 每个数字的序号都应该尽可能地小。

解题思路

  1. 对数组的副本进行去重,并从小到大排序
  2. 使用一个哈希表存储排序后数组中每个数字的排序
  3. 再次遍历原数组,在哈希表中查找出排序后返回

复杂度分析

  • 时间复杂度O(n log n),排序的时间复杂度是 O(n log n)
  • 空间复杂度O(n),用于存储哈希表和排序后的数组副本。

代码

/**
 * @param {number[]} arr
 * @return {number[]}
 */
var arrayRankTransform = function (arr) {
	const sorted = [...new Set(arr)].sort((a, b) => a - b);

	let map = new Map();
	for (let i = 0; i < sorted.length; i++) {
		map.set(sorted[i], i + 1);
	}

	return arr.map((i) => map.get(i));
};

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