2637. 有时间限制的 Promise 对象
2637. 有时间限制的 Promise 对象
题目
Given an asynchronous function fn
and a time t
in milliseconds, return a new time limited version of the input function. fn
takes arguments provided to the **time limited **function.
The time limited function should follow these rules:
- If the
fn
completes within the time limit oft
milliseconds, the time limited function should resolve with the result. - If the execution of the
fn
exceeds the time limit, the time limited function should reject with the string"Time Limit Exceeded"
.
Example 1:
Input:
fn = async (n) => {
await new Promise(res => setTimeout(res, 100));
return n * n;
}
inputs = [5]
t = 50
Output:
Explanation:
const limited = timeLimit(fn, t)
const start = performance.now()
let result;
try {
const res = await limited(...inputs)
result = {"resolved": res, "time": Math.floor(performance.now() - start)};
} catch (err) {
result = {"rejected": err, "time": Math.floor(performance.now() - start)};
}
console.log(result) // Output
The provided function is set to resolve after 100ms. However, the time limit is set to 50ms. It rejects at t=50ms because the time limit was reached.
Example 2:
Input:
fn = async (n) => {
await new Promise(res => setTimeout(res, 100));
return n * n;
}
inputs = [5]
t = 150
Output:
Explanation:
The function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.
Example 3:
Input:
fn = async (a, b) => {
await new Promise(res => setTimeout(res, 120));
return a + b;
}
inputs = [5,10]
t = 150
Output:
Explanation:
The function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.
Example 4:
Input:
fn = async () => {
throw "Error";
}
inputs = []
t = 1000
Output:
Explanation:
The function immediately throws an error.
Constraints:
0 <= inputs.length <= 10
0 <= t <= 1000
fn
returns a promise
题目大意
请你编写一个函数,它接受一个异步函数 fn
和一个以毫秒为单位的时间 t
。它应根据限时函数返回一个有 限时 效果的函数。函数 fn
接受提供给 限时 函数的参数。
限时 函数应遵循以下规则:
- 如果
fn
在t
毫秒的时间限制内完成,限时 函数应返回结果。 - 如果
fn
的执行超过时间限制,限时 函数应拒绝并返回字符串"Time Limit Exceeded"
。
提示:
0 <= inputs.length <= 10
0 <= t <= 1000
fn
返回一个 Promise 对象
解题思路
- 在
timeLimit
中返回了一个新的异步函数,并通过Promise
来控制结果的返回。 - 设置一个定时器
setTimeout
用来判断fn
是否超时,当超过给定的时间t
时,定时器将触发,拒绝 Promise 并返回"Time Limit Exceeded"
。 - 执行异步函数
fn
,如果fn
在规定时间内完成,无论是成功还是失败,都清理定时器以确保其不会再次执行。
复杂度分析
- 时间复杂度:取决于传入的
fn
的复杂度,假设为O(fn)
。 - 空间复杂度:
O(1)
,仅有定时器和 Promise 相关的内存开销。
代码
/**
* @param {Function} fn
* @param {number} t
* @return {Function}
*/
var timeLimit = function (fn, t) {
return async function (...args) {
return new Promise((resolve, reject) => {
// 超时后拒绝 Promise
const timer = setTimeout(() => reject('Time Limit Exceeded'), t);
// 执行异步函数 fn
fn(...args)
.then((result) => {
clearTimeout(timer); // 成功时清除定时器
resolve(result);
})
.catch((err) => {
clearTimeout(timer); // 失败时清除定时器
reject(err);
});
});
};
};
/**
* const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);
* limited(150).catch(console.log) // "Time Limit Exceeded" at t=100ms
*/
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